Optimal. Leaf size=303 \[ \frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{5 \sqrt{a+b x} (b c-a d)^{13/4}}-\frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 \sqrt{a+b x} (b c-a d)^{13/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 \sqrt [4]{c+d x} (b c-a d)^4}+\frac{77 d^2 \sqrt{a+b x}}{15 (c+d x)^{5/4} (b c-a d)^3}+\frac{11 d}{3 \sqrt{a+b x} (c+d x)^{5/4} (b c-a d)^2}-\frac{2}{3 (a+b x)^{3/2} (c+d x)^{5/4} (b c-a d)} \]
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Rubi [A] time = 0.289997, antiderivative size = 303, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.421, Rules used = {51, 63, 307, 224, 221, 1200, 1199, 424} \[ \frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 \sqrt{a+b x} (b c-a d)^{13/4}}-\frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 \sqrt{a+b x} (b c-a d)^{13/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 \sqrt [4]{c+d x} (b c-a d)^4}+\frac{77 d^2 \sqrt{a+b x}}{15 (c+d x)^{5/4} (b c-a d)^3}+\frac{11 d}{3 \sqrt{a+b x} (c+d x)^{5/4} (b c-a d)^2}-\frac{2}{3 (a+b x)^{3/2} (c+d x)^{5/4} (b c-a d)} \]
Antiderivative was successfully verified.
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Rule 51
Rule 63
Rule 307
Rule 224
Rule 221
Rule 1200
Rule 1199
Rule 424
Rubi steps
\begin{align*} \int \frac{1}{(a+b x)^{5/2} (c+d x)^{9/4}} \, dx &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}-\frac{(11 d) \int \frac{1}{(a+b x)^{3/2} (c+d x)^{9/4}} \, dx}{6 (b c-a d)}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{\left (77 d^2\right ) \int \frac{1}{\sqrt{a+b x} (c+d x)^{9/4}} \, dx}{12 (b c-a d)^2}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{\left (77 b d^2\right ) \int \frac{1}{\sqrt{a+b x} (c+d x)^{5/4}} \, dx}{20 (b c-a d)^3}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 (b c-a d)^4 \sqrt [4]{c+d x}}-\frac{\left (77 b^2 d^2\right ) \int \frac{1}{\sqrt{a+b x} \sqrt [4]{c+d x}} \, dx}{20 (b c-a d)^4}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 (b c-a d)^4 \sqrt [4]{c+d x}}-\frac{\left (77 b^2 d\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{a-\frac{b c}{d}+\frac{b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 (b c-a d)^4}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 (b c-a d)^4 \sqrt [4]{c+d x}}+\frac{\left (77 b^{3/2} d\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a-\frac{b c}{d}+\frac{b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 (b c-a d)^{7/2}}-\frac{\left (77 b^{3/2} d\right ) \operatorname{Subst}\left (\int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{b c-a d}}}{\sqrt{a-\frac{b c}{d}+\frac{b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 (b c-a d)^{7/2}}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 (b c-a d)^4 \sqrt [4]{c+d x}}+\frac{\left (77 b^{3/2} d \sqrt{\frac{d (a+b x)}{-b c+a d}}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+\frac{b x^4}{\left (a-\frac{b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 (b c-a d)^{7/2} \sqrt{a+b x}}-\frac{\left (77 b^{3/2} d \sqrt{\frac{d (a+b x)}{-b c+a d}}\right ) \operatorname{Subst}\left (\int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{b c-a d}}}{\sqrt{1+\frac{b x^4}{\left (a-\frac{b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 (b c-a d)^{7/2} \sqrt{a+b x}}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 (b c-a d)^4 \sqrt [4]{c+d x}}+\frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 (b c-a d)^{13/4} \sqrt{a+b x}}-\frac{\left (77 b^{3/2} d \sqrt{\frac{d (a+b x)}{-b c+a d}}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+\frac{\sqrt{b} x^2}{\sqrt{b c-a d}}}}{\sqrt{1-\frac{\sqrt{b} x^2}{\sqrt{b c-a d}}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 (b c-a d)^{7/2} \sqrt{a+b x}}\\ &=-\frac{2}{3 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/4}}+\frac{11 d}{3 (b c-a d)^2 \sqrt{a+b x} (c+d x)^{5/4}}+\frac{77 d^2 \sqrt{a+b x}}{15 (b c-a d)^3 (c+d x)^{5/4}}+\frac{77 b d^2 \sqrt{a+b x}}{5 (b c-a d)^4 \sqrt [4]{c+d x}}-\frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 (b c-a d)^{13/4} \sqrt{a+b x}}+\frac{77 b^{5/4} d \sqrt{-\frac{d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 (b c-a d)^{13/4} \sqrt{a+b x}}\\ \end{align*}
Mathematica [C] time = 0.0478869, size = 73, normalized size = 0.24 \[ -\frac{2 \left (\frac{b (c+d x)}{b c-a d}\right )^{9/4} \, _2F_1\left (-\frac{3}{2},\frac{9}{4};-\frac{1}{2};\frac{d (a+b x)}{a d-b c}\right )}{3 b (a+b x)^{3/2} (c+d x)^{9/4}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.044, size = 0, normalized size = 0. \begin{align*} \int{ \left ( bx+a \right ) ^{-{\frac{5}{2}}} \left ( dx+c \right ) ^{-{\frac{9}{4}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x + a\right )}^{\frac{5}{2}}{\left (d x + c\right )}^{\frac{9}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b x + a}{\left (d x + c\right )}^{\frac{3}{4}}}{b^{3} d^{3} x^{6} + a^{3} c^{3} + 3 \,{\left (b^{3} c d^{2} + a b^{2} d^{3}\right )} x^{5} + 3 \,{\left (b^{3} c^{2} d + 3 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} x^{4} +{\left (b^{3} c^{3} + 9 \, a b^{2} c^{2} d + 9 \, a^{2} b c d^{2} + a^{3} d^{3}\right )} x^{3} + 3 \,{\left (a b^{2} c^{3} + 3 \, a^{2} b c^{2} d + a^{3} c d^{2}\right )} x^{2} + 3 \,{\left (a^{2} b c^{3} + a^{3} c^{2} d\right )} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x + a\right )}^{\frac{5}{2}}{\left (d x + c\right )}^{\frac{9}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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